| Andrew Scull | b4b6d4a | 2019-01-02 15:54:55 +0000 | [diff] [blame] | 1 | /* SPDX-License-Identifier: GPL-2.0 */ |
| 2 | #ifndef _ASM_IA64_TIMEX_H |
| 3 | #define _ASM_IA64_TIMEX_H |
| 4 | |
| 5 | /* |
| 6 | * Copyright (C) 1998-2001, 2003 Hewlett-Packard Co |
| 7 | * David Mosberger-Tang <davidm@hpl.hp.com> |
| 8 | */ |
| 9 | /* |
| 10 | * 2001/01/18 davidm Removed CLOCK_TICK_RATE. It makes no sense on IA-64. |
| 11 | * Also removed cacheflush_time as it's entirely unused. |
| 12 | */ |
| 13 | |
| 14 | #include <asm/intrinsics.h> |
| 15 | #include <asm/processor.h> |
| 16 | |
| 17 | typedef unsigned long cycles_t; |
| 18 | |
| 19 | extern void (*ia64_udelay)(unsigned long usecs); |
| 20 | |
| 21 | /* |
| 22 | * For performance reasons, we don't want to define CLOCK_TICK_TRATE as |
| 23 | * local_cpu_data->itc_rate. Fortunately, we don't have to, either: according to George |
| 24 | * Anzinger, 1/CLOCK_TICK_RATE is taken as the resolution of the timer clock. The time |
| 25 | * calculation assumes that you will use enough of these so that your tick size <= 1/HZ. |
| 26 | * If the calculation shows that your CLOCK_TICK_RATE can not supply exactly 1/HZ ticks, |
| 27 | * the actual value is calculated and used to update the wall clock each jiffie. Setting |
| 28 | * the CLOCK_TICK_RATE to x*HZ insures that the calculation will find no errors. Hence we |
| 29 | * pick a multiple of HZ which gives us a (totally virtual) CLOCK_TICK_RATE of about |
| 30 | * 100MHz. |
| 31 | */ |
| 32 | #define CLOCK_TICK_RATE (HZ * 100000UL) |
| 33 | |
| 34 | static inline cycles_t |
| 35 | get_cycles (void) |
| 36 | { |
| 37 | cycles_t ret; |
| 38 | |
| 39 | ret = ia64_getreg(_IA64_REG_AR_ITC); |
| 40 | return ret; |
| 41 | } |
| 42 | |
| 43 | extern void ia64_cpu_local_tick (void); |
| 44 | extern unsigned long long ia64_native_sched_clock (void); |
| 45 | |
| 46 | #endif /* _ASM_IA64_TIMEX_H */ |